LeetCode-102. Binary Tree Level Order Traversal

LeetCode-102. Binary Tree Level Order Traversal

Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level).

For example: Given binary tree ​​​[3,9,20,null,null,15,7]​​,

3 / \ 9 20 / \ 15 7

return its level order traversal as:

[ [3], [9,20], [15,7]]

题解：

class Solution {public: vector> levelOrder(TreeNode* root) { queue q; if (root == NULL) { return {}; } q.push(root); int cnt = 1; vector v; vector> res; while(q.empty() == false) { if (cnt >= 0) { cnt--; TreeNode *t = q.front(); q.pop(); v.push_back(t->val); if (t->left != NULL) { q.push(t->left); } if (t->right != NULL) { q.push(t->right); } } if (cnt == 0) { res.push_back(v); v.clear(); cnt = q.size(); } } return res; }};

版权声明：本文内容由网络用户投稿，版权归原作者所有，本站不拥有其著作权，亦不承担相应法律责任。如果您发现本站中有涉嫌抄袭或描述失实的内容，请联系我们jiasou666@gmail.com 处理，核实后本网站将在24小时内删除侵权内容。