c语言sscanf函数的用法是什么
273
2022-12-01
134. Gas Station
There are N gas stations along a circular route, where the amount of gas at station i is gas[i].
You have a car with an unlimited gas tank and it costs cost[i] of gas to travel from station i to its next station (i+1). You begin the journey with an empty tank at one of the gas stations.
Return the starting gas station’s index if you can travel around the circuit once, otherwise return -1.
Note: The solution is guaranteed to be unique.
class Solution { public int canCompleteCircuit(int[] gas, int[] cost) { if (gas == null || cost == null || gas.length == 0 || cost.length == 0) { return -1; } int sum = 0; int total = 0; int index = -1; for(int i = 0; i class Solution { public int canCompleteCircuit(int[] gas, int[] cost) { int currentNetSum = 0; int startIdx = -1; int totalNetDiff = 0; for(int idx = 0; idx < gas.length; idx++) { int currentDiff = gas[idx] - cost[idx]; currentNetSum += currentDiff; totalNetDiff += currentDiff; if(currentNetSum < 0) { currentNetSum = 0; startIdx = -1; continue; } startIdx = startIdx == -1 ? idx: startIdx; } return startIdx != -1 && totalNetDiff >= 0 ? startIdx: -1; }}
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