YTU 2905: The Sum of 1...N

YTU 2905: The Sum of 1...N

2905: The Sum of 1...N

时间限制: 1 Sec   内存限制: 128 MB

提交: 281

解决: 51

题目描述

Given an integer n,your task is to calculate 1+2+...+N;

输入

The first line of input contains an integer T, indicating the number of test cases (T<=20)

The each test case contains a single positive integer N(N<=2^32).

输出

For each input you should output the sum of 1+2+...+N in one line.(The result must less than 2^63)

样例输入

2101

样例输出

551

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#include using namespace std;int main(){ unsigned long long n; int T; cin>>T; while(T--) { cin>>n; n=n*(n+1)/2; cout<

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